2x^2+4x+12=10

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Solution for 2x^2+4x+12=10 equation:


Simplifying
2x2 + 4x + 12 = 10

Reorder the terms:
12 + 4x + 2x2 = 10

Solving
12 + 4x + 2x2 = 10

Solving for variable 'x'.

Reorder the terms:
12 + -10 + 4x + 2x2 = 10 + -10

Combine like terms: 12 + -10 = 2
2 + 4x + 2x2 = 10 + -10

Combine like terms: 10 + -10 = 0
2 + 4x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(1 + 2x + x2) = 0

Factor a trinomial.
2((1 + x)(1 + x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-1, -1}

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